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THE EE 101 CHALLENGE/FINAL EXAM QUESTION BANK TRANSIENTS

, by questionbank2u

SAN JOSE STATE UNIVERSITY
College of Engineering
ELECTRICAL ENGINEERING DEPARTMENT


THE EE 101 CHALLENGE/FINAL EXAM QUESTION BANK


EE 101 (Circuit Concepts and Problem Solving) is a one-unit, credit/no-credit course that is a prerequisite for EE 110 (Network Analysis) and EE 112 (Linear Systems). The prerequisites for EE 101 are a grade of C or better in EE 98 or equivalent.
To obtain credit for EE 101, students are required to

(1) enroll in the EE 101 semester course and 
(2) achieve a passing score on the examination.

Note that students can either

(a) take the examination at the end of a semester of their enrollment, or 
(b) "challenge" the course by taking the examination at the beginning of a semester.

Students are required to be registered in the EE 101 course in the semester that they take and pass the exam.
Well prepared students are encouraged to "challenge" the course. To help students prepare for this exam, this web site provides a collection of 305 questions and their answers. In every case, the first answer in the multiple-choice list of five choices is the correct answer. To avoid being biased by knowing the right answer ahead of time, we recommend that you work out your solution to each problem before looking at the answers.
The examination for EE 101 is closed book and closed notes. Only student ID and basic calculators are allowed. The questions on the actual exam will be created by selecting questions from the EE 101 Question Bank and modifying the questions slightly. Typical modifications include, but are not limited to, changing the numerical values of parameters and randomizing the answer sequence.
The following categories are:



TRANSIENTS
The following 50 questions concern first-order and second-order transients in circuits. In this version of the exam, the first choice is always the correct one. In the actual exam, the correct choice could be in any position, and there may be other minor changes to the problems.

1. The circuit is in equilibrium for t < 0, and the switch opens when t = 0. If V0 = 2 V, R = 2 W and C = 0.5 F, the voltage v(t) (in volts) for t > 0 is
  1. 2 e-t
  2. 2 (1 - e-t)
  3. 2 (1 - e-4t)
  4. e-t/4
  5. 2 e-t/4


2. The circuit is in equilibrium for t < 0, and the switch closes when t = 0. If I0 = 3 A, R = 2 W and L = 2 H, the current i(t) (in amperes) for t > 0 is
  1. 3 e-t
  2. 3 (1 - e-t)
  3. 3 (1 - e-4t)
  4. 3 (1 - e-t/4)
  5. 3 e-t/4


3. The voltage v(t) is zero for t < 0, and the switch closes when t = 0. If V0 = 10 V, R = 2 W and C = 2 F, the voltage v(t) (in volts) for t > 0 is
  1. 10 (1 - e-t/4)
  2. 10 e-t/4
  3. 10 (1 - e-4t)
  4. 10 e-4t
  5. 10 (1 + e-t/4)


4. The circuit is in equilibrium for t < 0, and the switch moves up when t = 0. If I0 = 5 A, R = 1 W and L = 0.5 H, the current i(t) (in amperes) for t > 0 is
  1. 5 (1 - e-2t)
  2. 5 e-2t
  3. 5 e-t/2
  4. 5 (1 - e-t/2)
  5. -5 e-2t


5. The circuit is in equilibrium for t < 0, and the switch opens when t = 0. If V0 = 10 V, R1 = 2 W, R2 = 2 W and C = 0.5 F, the voltage v(t) (in volts) for t > 0 is
  1. 10 e-t/2
  2. 10 e-2t
  3. 10 (1 - e-2t)
  4. 10 (1 - e-t/2)
  5. 10 (1 + e-t/2)


6. The circuit is in equilibrium for t < 0, and the switch closes when t = 0. If V0 = 10 V, R1 = 3 W, R2 = 1 W and C = 1 F, the voltage v(t) (in volts) for t > 0 is
  1. 10 (1 - e-t)
  2. 10 e-t
  3. 10 e-2t
  4. 10 (1 - e-3t)
  5. 10 e-3t


7. The circuit is in equilibrium for t < 0, and the switch closes when t = 0. If I0 = 10 A, R1 = 6 W, R2 = 3 W and L = 0.5 H, the current i(t) (in amperes) for t > 0 is
  1. 10 e-4t
  2. 10 e-2t
  3. 10 e-t
  4. 10 e-9t
  5. 10 e-3t


8. The circuit is in equilibrium for t < 0, and the switch opens when t = 0. If I0 = 2 A, R1 = 2 W, R2 = 2 W and L = 4 H, the current i(t) (in amperes) for t > 0 is
  1. 2 (1 - e-t/2)
  2. 1 - e-t/2
  3. 1 + e-t/2
  4. 2 (1 - e-2t)
  5. 2 (1 - e-t/4)


9. The circuit is in equilibrium for t < 0, and the switch opens when t = 0. If V0 = 4 V, R1 = 2 W, R2 = 2 W and C = 2 F, the voltage v(t) (in volts) for t > 0 is
  1. 2 e-t/4
  2. 2 (1 - e-t/4)
  3. 2 (1 + e-4t)
  4. 2 (1 - e-4t)
  5. 2 e-4t


10. The circuit is in equilibrium for t < 0, and the switch closes when t = 0. If V0 = 4 V, R1 = 2 W, R2 = 2 W and C = 2 F, the voltage v(t) (in volts) for t > 0 is
  1. 2(1 - e-t/2)
  2. 2 e-t/2
  3. 2 (1 - e-t)
  4. 2 (1 - e-2t)
  5. 2 e-2t


11. The circuit is in equilibrium for t < 0, and the switch closes when t = 0. If I0 = 4 A, R1 = 2 W, R2 = 2 W and L = 1 H, the current i(t) (in amperes) for t > 0 is
  1. 2 e-2t
  2. 2 e-t/2
  3. 2 e-4t
  4. 2 e-t/4
  5. 2 (1 - e-2t)


12. The circuit is in equilibrium for t < 0, and the switch opens when t = 0. If I0 = 4 A, R1 = 2 W, R2 = 2 W and L = 2 H, the current i(t) (in amperes) for t > 0 is
  1. 2 (1 - e-2t)
  2. 2 e-2t
  3. 2 e-t/2
  4. 2 (1 - e-t/2)
  5. 2 e-t/4


13. The circuit is in equilibrium for t < 0, and the switch opens when t = 0. If I0 = 4 A, R1 = 2 W, R2 = 2 W and C = 0.5 F, the voltage v(t) (in volts) for t > 0 is
  1. 4 (2 - e-t)
  2. 8 (1 - e-t)
  3. 4 (2 + e-t)
  4. 2 (4 - e-t)
  5. 4 (2 - e-2t)


14. The circuit is in equilibrium for t < 0, and the switch closes when t = 0. If I0 = 4 A, R1 = 2 W, R2 = 2 W and C = 0.5 F, the voltage v(t) (in volts) for t > 0 is
  1. 4 (1 + e-2t)
  2. 4 (1 - e-2t)
  3. 4 (1 + e-t)
  4. 4 (1 - e-t)
  5. 4 e-t


15. The circuit is in equilibrium for t < 0, and the switch opens when t = 0. If V0 = 4 V, R1 = 2 W, R2 = 2 W and L = 2 H, the current i(t) (in amperes) for t > 0 is
  1. 1 + e-2t
  2. 1 - e-2t
  3. 1 + e-t
  4. 1 + e-2t
  5. e -2t


16. The circuit is in equilibrium for t < 0, and the switch closes when t = 0. If V0 = 4 V, R1 = 2 W, R2 = 2 W and L = 2 H, the current i(t) (in amperes) for t > 0 is
  1. 2 - e-t
  2. 2 (1 - e-t)
  3. 2 (1 + e-t)
  4. 2 e-t
  5. 2 e-2t


17. The circuit is in equilibrium for t < 0, and the switch closes when t = 0. If V0 = 4 V, R1 = 2 W, R2 = 2 W and C = 0.5 F, the voltage v(t) (in volts) for t > 0 is
  1. 2 (1 + e-2t)
  2. 2 (1 - e-2t)
  3. 2 (1 + e-t)
  4. 2 (1 - e-t)
  5. 2 e-2t


18. The circuit is in equilibrium for t < 0, and the switch opens when t = 0. If V0 = 4 V, R1 = 2 W, R2 = 2 W and C = 0.5 F, the voltage v(t) (in volts) for t > 0 is
  1. 2 ( 2 - e-t)
  2. 2 (1 - e-t)
  3. 2 (2 + e-t)
  4. 2 (2 - e-4t)
  5. 2 (2 - e-t/4)


19. The circuit is in equilibrium for t < 0, and the switch opens when t = 0. If I0 = 4 A, R1 = 2 W, R2 = 2 W and L = 2 H, the current i(t) (in amperes) for t > 0 is
  1. 2 (1 + e-2t)
  2. 2 (1 - e-2t)
  3. 2 (1 + e-t)
  4. 2 (1 - e-t)
  5. 2 (1 + e-4t)


20. The circuit is in equilibrium for t < 0, and the switch closes when t = 0. If I0 = 4 A, R1 = 2 W, R2 = 2 W and L = 2 H, the current i(t) (in amperes) for t > 0 is
  1. 2 (2 - e-t)
  2. 2 (2 + e-t)
  3. 2 (2 - e-2t)
  4. 2 (2 + e-2t)
  5. 2 (2 - e-t/2)


21. In the circuit shown, I0 = 4 A, R = 2 W, and L = 0.5 H. If i(0) = 2 A, the derivative di/dt (in amperes/second) at t = 0 is
  1. 8
  2. 4
  3. 2
  4. -8
  5. -4


22. In the circuit shown, I0 = 4 A, R = 2 W, and C = 2 F. If v(0) = 4 V, the derivative dv/dt (in volts/second) at t = 0 is
  1. 1
  2. 2
  3. -1
  4. -2
  5. 0.5


23. In the circuit shown, V0 = 4 V, R = 2 W, and C = 0.5 F. If v(0) = 2 V, the derivative dv/dt (in volts/second) at t = 0 is
  1. 2
  2. 1
  3. -2
  4. -1
  5. 0


24. In the circuit shown, V0 = 4 V, R = 2 W, and L = 2 H. If i(0) = 1 A, the derivative di/dt (in amperes/second) at t = 0 is
  1. 1
  2. 2
  3. -1
  4. -2
  5. 0


25. In the circuit shown, V0 = 4 V, R1 = 2 W, R2 = 2 W, and C = 0.5 F. If v(0) = 1 V, the derivative dv/dt (in volts/second) at t = 0 is
  1. 2
  2. 1
  3. -1
  4. -2
  5. 4


26. In the circuit shown, V0 = 4 V, R1 = 2 W, R2 = 2 W, and L = 2 H. If i(0) = 2 A, the derivative di/dt (in amperes/second) at t = 0 is
  1. 0
  2. 1
  3. -1
  4. -2
  5. 2


27. In the circuit shown, I0 = 4 A, R1 = 2 W, R2 = 2 W, and C = 0.25 F. If v(0) = 1 V, the derivative dv/dt (in volts/second) at t = 0 is
  1. 7
  2. -7
  3. 4
  4. -4
  5. 0


28. In the circuit shown, I0 = 4 A, R1 = 2 W, R2 = 2 W, and L = 2 H. If i(0) = 1 A, the derivative di/dt (in amperes/second) at t = 0 is
  1. 2
  2. 1
  3. -1
  4. -2
  5. 0


29. In the circuit shown, R = 2 W, L = 2 H and C = 0.5 F. If i(0) = 1 A and v(0) = 1 V, the second derivative d2v/dt2 (in volts/second2) at t = 0 is
  1. -3
  2. 3
  3. -2
  4. 2
  5. 0


30. In the circuit shown, R = 2 W, L = 2 H and C = 0.5 F. If i(0) = 1 A and v(0) = 2 V, the second derivative d2i/dt2 (in amperes/second2) at t = 0 is
  1. -2
  2. 2
  3. -1
  4. 1
  5. 0


31. In the circuit shown, V0 = 4 V, R1 = 2 W, R2 = 2 W, and C = 0.5 F. If v(0) = 1 V, the derivative dv/dt (in volts/second) at t = 0 is
  1. 2
  2. 1
  3. -1
  4. -2
  5. 0


32. In the circuit shown, R1 = 2 W, R2 = 2 W, L = 2 H and I0 = 4 A. If i(0) = 1 A, the derivative di/dt (in amperes/second) at t = 0 is
  1. 2
  2. 1
  3. -1
  4. -2
  5. 0


33. In the circuit shown, I0 = 4 A, R = 2 W, and C = 0.5 F. If v(0) = 3 V, the derivative dv/dt (in volts/second2) at t = 0 is
  1. 5
  2. -5
  3. 4
  4. -4
  5. 0


34. In the circuit shown, V0 = 4 V, R = 2 W, and L = 2 H. If i(0) = 3 A, the derivative di/dt (in amperes/second) at t = 0 is
  1. -1
  2. 1
  3. 2
  4. -2
  5. 0


35. In the circuit shown, V0 = 10 V, R1 = 2 W, R2 = 2 W, R3 = 2 W, C1 = 0.5 F, and C2 = 0.25 F. If the circuit is in steady-state equilibrium, the voltage v2(t) (in volts) is
  1. 10/3
  2. -10/3
  3. 3/10
  4. -3/10
  5. 2


36. In the circuit shown, I0 = 10 A, R1 = 2 W, R2 = 2 W, R3 = 2 W, L1 = 2 H, and L2 = 1 H. If the circuit is in steady-state equilibrium, the current i2(t) (in amperes) is
  1. 10/3
  2. -10/3
  3. 3/10
  4. -3/10
  5. 2


37. In the circuit shown, V0 = 10 V, R1 = 2 W, R2 = 2 W, R3 = 2 W, C = 0.5 F, and L = 2 H. If the circuit is in steady-state equilibrium, the voltage v(t) (in volts) is
  1. 5
  2. -5
  3. 3
  4. -3
  5. 0


38. In the circuit shown, I0 = 10 A, R1 = 2 W, R2 = 2 W, R3 = 2 W, C = 2 F, and L = 0.5 H. If the circuit is in steady-state equilibrium, the current i(t) (in amperes) is
  1. 5
  2. -5
  3. 3
  4. -3
  5. 0


39. In the circuit shown, R1 = 1/12 W, R2 = 1/6 W, C1 = 9 F, and C2 = 2 F. If the initial voltages v1(0) and v2(0) are not zero, the voltage v2(t) has the form
  1. A1e-t + A2 e-4t
  2. A cos(2t + q)
  3. A e-t cos(4t + q)
  4. A1e-t + A2-2t
  5. (A1 + A2t) e-2t


40. In the circuit shown, R1 = 12 W, R2 = 6 W, L1 = 9 H, and L2 = 2 H. If the initial currents i1(0) and i2(0) are not zero, the current i2(t) has the form
  1. A1e-t + A2 e-4t
  2. A cos(2t + q)
  3. A e-t cos(4t + q)
  4. A1e-t + A2-2t
  5. (A1 + A2t) e-2t


41. In the circuit shown, R = 5 W, L = 1 H and C = 0.25 F. If the initial current i(0) is not zero, the current i(t) has the form
  1. A1e-t + A2 e-4t
  2. A cos(2t + q)
  3. A e-t cos(4t + q)
  4. A1e-t + A2-2t
  5. (A1 + A2t) e-2t


42. In the circuit shown, R = 4 W, L = 1 H and C = 0.25 F. If the initial current i(0) is not zero, the current i(t) has the form
  1. (A1 + A2t) e-2t
  2. A1e-t + A2 e-2t
  3. A cos(2t + q)
  4. A e-2t cos(2t + q)
  5. A1e-t + A22t


43. In the circuit shown, R = 4 W, L = 1 H and C = 0.125 F. If the initial current i(0) is not zero, the current i(t) has the form
  1. A e-2t cos(2t + q)
  2. (A1 + A2t) e-2t
  3. A1e-t + A2 e-2t
  4. A cos(2t + q)
  5. A1e-t + A22t


44. In the circuit shown, R = 0 W, L = 1 H and C = 0.25 F. If the initial current i(0) is not zero, the current i(t) has the form
  1. A cos(2t + q)
  2. A e-2t cos(2t + q)
  3. (A1 + A2t) e-2t
  4. A1e-t + A2 e-2t
  5. A1e-t + A22t


45. In the circuit shown, R = -4 W, L = 1 H and C = 0.125 F. If the initial current i(0) is not zero, the current i(t) has the form
  1. A e2t cos(2t + q)
  2. A e-2t cos(2t + q)
  3. A cos(2t + q)
  4. (A1 + A2t) e-2t
  5. A1e-t + A2 e-2t


46. In the circuit shown, R = 7 W, L = 8 H and C = 1/56 F. If the initial voltage v(0) is not zero, the voltage v(t) has the form
  1. A1e-t + A2 e-7t
  2. A cos(7t + q)
  3. A e-t cos(7t + q)
  4. A1e-t + A2-2t
  5. (A1 + A2t) e-2t


47. In the circuit shown, R = 2 W, L = 4 H and C = 0.25 F. If the initial voltage v(0) is not zero, the voltage v(t) has the form
  1. (A1 + A2t) e-t
  2. A1e-t + A2 e-2t
  3. A cos(2t + q)
  4. A e-2t cos(2t + q)
  5. A1e-t + A22t


48. In the circuit shown, R = 2 W, L = 1 H and C = 0.125 F. If the initial voltage v(0) is not zero, the voltage v(t) has the form
  1. A e-2t cos(2t + q)
  2. A e2t cos(2t + q)
  3. (A1 + A2t) e-2t
  4. A1e-t + A2 e-2t
  5. A cos(2t + q)


49. In the circuit shown, R is infinite, L = 1 H and C = 1/4 F. If the initial voltage v(0) is not zero, the voltage v(t) has the form
  1. A cos(2t + q)
  2. A e-2t cos(2t + q)
  3. A e2t cos(2t + q)
  4. (A1 + A2t) e-2t
  5. A1e-t + A2 e-2t


50. In the circuit shown, R = -2 W, L = 1 H and C = 0.125 F. If the initial voltage v(0) is not zero, the voltage v(t) has the form
  1. A e2t cos(2t + q)
  2. A e-2t cos(2t + q)
  3. A cos(2t + q)
  4. (A1 + A2t) e-2t
  5. A1e-t + A2 e-2t




End of Questions on Transients

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