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THE EE 101 CHALLENGE/FINAL EXAM QUESTION BANK AC CIRCUITS

, by questionbank2u

SAN JOSE STATE UNIVERSITY
College of Engineering
ELECTRICAL ENGINEERING DEPARTMENT


THE EE 101 CHALLENGE/FINAL EXAM QUESTION BANK


EE 101 (Circuit Concepts and Problem Solving) is a one-unit, credit/no-credit course that is a prerequisite for EE 110 (Network Analysis) and EE 112 (Linear Systems). The prerequisites for EE 101 are a grade of C or better in EE 98 or equivalent.
To obtain credit for EE 101, students are required to

(1) enroll in the EE 101 semester course and 
(2) achieve a passing score on the examination.

Note that students can either

(a) take the examination at the end of a semester of their enrollment, or 
(b) "challenge" the course by taking the examination at the beginning of a semester.

Students are required to be registered in the EE 101 course in the semester that they take and pass the exam.
Well prepared students are encouraged to "challenge" the course. To help students prepare for this exam, this web site provides a collection of 305 questions and their answers. In every case, the first answer in the multiple-choice list of five choices is the correct answer. To avoid being biased by knowing the right answer ahead of time, we recommend that you work out your solution to each problem before looking at the answers.
The examination for EE 101 is closed book and closed notes. Only student ID and basic calculators are allowed. The questions on the actual exam will be created by selecting questions from the EE 101 Question Bank and modifying the questions slightly. Typical modifications include, but are not limited to, changing the numerical values of parameters and randomizing the answer sequence.
The following categories are:



AC CIRCUITS

The following questions concern AC circuit analysis. All operational amplifiers are ideal. In this version of the exam, the first choice is always the correct one. In the actual exam, the correct choice could be in any position, and there may be other changes to the choices.


1. If R = 4 W, X1 = 2 W, and X2 = -5 W , the equivalent impedance Zeq (in ohms) at terminals a and b is

  1. 4 - j 2
  2. 4 + j 2
  3. 4 - j 3
  4. 4 + j 3
  5. 4 + j 0


2. If R1 = 2 W, X1 = 1 W, R2 = 2 W, and X2 = -2 W , the equivalent impedance Zeq (in ohms) at terminals a and b is

  1. 3 + j 0
  2. 3 + j 2
  3. 3 - j 2
  4. 0 - j 2
  5. 0 + j 2


3. If R = 2 W, L = 0.2 H, and C = 0.05 F, and if the radian frequency is w = 10 rad/s, the equivalent impedance Zeq (in ohms) at terminals a and b is

  1. 1 - j
  2. 1 + j
  3. 2 - j 2
  4. 2 + j 2
  5. 2 + j 0


4. If R1 = 2 W, R2 = 2 W, L = 0.5 H, and C = 0.125 F, and if the radian frequency is w = 4 rad/s, the equivalent impedance Zeq (in ohms) at terminals a and b is

  1. 4 - j 2
  2. 4 + j 2
  3. 2 - j 4
  4. 2 + j 4
  5. 2 + j 0


5. If R = 2 W, X1 = 2 W, X2 = -2 W , and Is = 1 + j 0 A, the phasor voltage V (in volts) is

  1. 1 + j
  2. 1 - j
  3. 0 + j
  4. 0 - j
  5. 2 + j 0


6. If R1 = 2 W, R2 = 10 W, X1 = -8 W, X2 = 5 W , and Is = 2+ j 0 A, the phasor voltage V (in volts) is

  1. 8 - j 8
  2. 8 + j 8
  3. -8 + j 8
  4. -8 - j 8
  5. 8 + j 0


7. If R = 4 W, L = 0.5 H, C = 0.1 F, and i s (t) = 3 cos(2 t) A, the forced response for the voltage v(t) (in volts) is

  1. 12 cos(2 t - 45o)
  2. 12 cos(2 t + 45o)
  3. 12 cos(2 t - 90o)
  4. 12 cos(2 t + 90o)
  5. 12 cos(2 t)


8. If R = 8 W, L = 0.5 H, C = 1/12 F, and i s (t) = 2 cos(4 t) A, the forced response for the voltage v(t) (in volts) is

  1. 20 cos(4 t + 36.9o)
  2. 20 cos(4 t - 36.9o)
  3. 20 cos(4 t - 53.1o)
  4. 20 cos(4 t + 53.1o)
  5. 20 cos(4 t )


9. If R = 2 W, X1 = 10 W, X2 = -4 W , and Vs = 20 + j 0 V, the phasor current I (in amperes) is

  1. 2 + j 2
  2. 2 - j 2
  3. 3 - j 4
  4. 3 + j 4
  5. 4 - j 3


10. If R = 4 W, X1 = 2 W, X2 = 4 W , and Vs = 20 + j 0 V, the phasor current I (in amperes) is

  1. 2 - j 4
  2. 2 + j 4
  3. 4 - j 2
  4. 4 + j 2
  5. 4 + j 4


11. If R = 1 W, L = 0.5 H, C = 1 F, and vs (t) = cos(t) V, the forced response for the current i(t) (in amperes) is

  1. 2 cos(t)
  2. 2 cos(t - 45o)
  3. 2 cos(t +45o)
  4. 2 cos(t - 90o)
  5. 2 cos(t + 90o)


12. If R = 1 W, L = 1 H, C = 1 F, and vs (t) = 2 cos(t) V, the forced response for the current i(t) (in amperes) is

  1. cos(t)
  2. 2 cos(t)
  3. cos(t + 45o)
  4. 2 cos(t + 45o)
  5. 2 cos(t - 45o)


13. If R = 2 W, X1 = 2 W, X2 = -2 W , and Vs = 1 + j 0 V, the phasor voltage V2 (in volts) is

  1. 0 - j
  2. 0 + j
  3. 1 + j
  4. 1 - j
  5. 2 + j 0


14. If R1 = 2 W, R2 = 2 W, X1 = -1 W, X2 = 2 W , and Vs = 2 + j 0 V, the phase angle (in degrees) of the phasor voltage V is

  1. 45
  2. -45
  3. 53.1
  4. -53.1
  5. 36.9


15. If R = 2 W, L = 0.2 H, C = 0.05 F, and vs(t) = 2 cos(10 t) V, the forced response for the voltage v(t) (in volts) is

  1. 2 cos(10 t + 90o)
  2. 2 cos(10 t - 90o)
  3. cos(10 t + 45o)
  4. cos(10 t - 45o)
  5. cos(10 t)


16. If L1 = 4 H, L2 = 2 H, C = 0.125 F, and vs(t) = 4 cos(2 t) V, the forced response for the voltage v(t) (in volts) is

  1. 2 cos(2 t - 180o)
  2. 2 cos(2 t - 45o)
  3. 2 cos(2 t + 45o)
  4. 2 cos(2 t + 90o)
  5. 2 cos(2 t)


17. If R = 4 W, X = -4 W , and Is = 6 + j 0 A, the phasor current I (in amperes) is

  1. 3 - j 3
  2. 3 + j 3
  3. -3 - j 3
  4. -3 + j 3
  5. 3 + j 0


18. If R = 1 W, X = 3 W , and Is = 10+ j 0 A, the phasor current I (in amperes) is

  1. -9 - j 3
  2. -9 + j 3
  3. 9 - j 3
  4. 9 + j 3
  5. 6 + j 6


19. If R = 1 W, L = 2 H, C = 0.5 F, and is (t) = 4 cos(t) A, the forced response for the current i(t) (in amperes) is

  1. 2 cos(t +90o)
  2. 2 cos(t - 90o)
  3. 2 cos(t + 45o)
  4. 2 cos(t - 45o)
  5. 2 cos(t)


20. If R = 4 W, L = 0.5 H, C = 0.1 F, and is (t) = 4 cos(2 t) A, the forced response for the current i(t) (in amperes) is

  1. 4 cos(2 t + 45o)
  2. 4 cos(2 t - 45o)
  3. 4 cos(2 t + 90o)
  4. 4 cos(2 t - 90o)
  5. 4 cos(2 t)


21. If R = 4 W, X1 = 2 W , X2 = -5 W , and Vs = 5+ j 0 V, the Thevenin equivalent impedance ZTh (in ohms) at terminals a and b is

  1. 4 - j 2
  2. 4 + j 2
  3. 0 + j 5
  4. 0 - j 5
  5. 4 - j 3


22. If R = 4 W, X1 = 2 W , X2 = -5 W , and Is = 2+ j 0 A, the Thevenin equivalent impedance ZTh (in ohms) at terminals a and b is

  1. 0 - j 5
  2. 0 + j 5
  3. 4 - j 2
  4. 4 + j 2
  5. 4 - j 3


23. If R = 4 W, X = 2 W , and m = 0.5, the Thevenin equivalent impedance ZTh (in ohms) at terminals a and b is

  1. 8 + j 4
  2. 8 - j 4
  3. 4 + j 8
  4. 4 - j 8
  5. 4 + j 2


24. If X1 = 1 W, X2 = -2 W, and g = 0.5 S, the Thevenin equivalent impedance ZTh (in ohms) at terminals a and b is

  1. 1 - j
  2. 1 + j
  3. -1 - j
  4. -1 + j
  5. 1 + j 0


25. If R = 4 W, X1 = 2 W, X2 = -5 W, and Vs = 5+ j 0 V, the Thevenin equivalent voltage VTh (in volts) at terminals a and b is

  1. 3 - j 4
  2. 3 + j 4
  3. 4 + j 3
  4. 4 - j 3
  5. 0


26. If R = 4 W, X1 = 2 W, X2 = -5 W, and Is = 2+ j 0 A, the Thevenin equivalent voltage VTh (in volts) at terminals a and b is

  1. 0 - j 10
  2. 0 + j 10
  3. 8 - j 6
  4. 8 + j 6
  5. 0


27. If R = 4 W, X = 2 W, and m = 0.5, the Thevenin equivalent voltage VTh (in volts) at terminals a and b is

  1. 0
  2. 0.5 + j 0
  3. 0 + j 0.5
  4. 0 - j 0.5
  5. 1 + j


28. If X1 = 1 W, X2 = -2 W and g = 0.5 S, the Thevenin equivalent voltage VTh (in volts) at terminals a and b is

  1. 0
  2. 0 + j 0.5
  3. 0 - j 0.5
  4. 1 - j 2
  5. 1 + j 2


29. If R = 4 W, X1 = 2 W, X2 = -5 W, and Vs = 20 + j 0 V, the Norton equivalent current IN (in amperes) at terminals a and b is

  1. 4 - j 2
  2. 4 + j 2
  3. -4 + j 2
  4. -4 - j 2
  5. 0


30. If R = 4 W, X1 = 2 W, X2 = -5 W, and Is = 2 + j 0 A, the Norton equivalent current IN (in amperes) at terminals a and b is

  1. 2 + j 0
  2. 4 - j 2
  3. 4 + j 2
  4. 0 - j 10
  5. 0


31. If R = 4 W, X = 2 W, and m = 0.5, the Norton equivalent current IN (in amperes) at terminals a and b is

  1. 0
  2. 0 + j 0.5
  3. 0 - j 0.5
  4. 0.1 - j 0.05
  5. 0.1 + j 0.05


32. If X1 = 1 W, X2 = -2 W and g = 0.5 S, the Norton equivalent current IN (in amperes) at terminals a and b is

  1. 0
  2. 1 - j 2
  3. 1 + j 2
  4. 0 + j 0.5
  5. 0 - j 0.5


33. If R = 5 W, X1 = -5 W, X2 = 5 W, Vs = 0 + j 15 V, and Is = 1 + j A, the phasor current I (in amperes) is

  1. 0 + j
  2. 0 - j
  3. 0 + j 5
  4. 0 - j 5
  5. 2 + j 0


34. If R = 5 W, X1 = -5 W, X2 = 5 W, Vs = 0 + j 15 V, and Is = 1 + j A, the phasor current I (in amperes) is

  1. 0 - j 5
  2. 0 + j 5
  3. 0 + j
  4. 0 - j
  5. 2 + j 0


35. If Vs = 12+ j 0 V, X1 = 3 W, X2 = -2 W, and r = 5 W, the phasor current I2 (in amperes) is

  1. 10 + j 0
  2. -10 + j 0
  3. 5 + j 5
  4. 5 - j 5
  5. 0


36. If Is = 2+ j 0 A, X = 5 W, R = 10 W, and m = 40, the phasor current I2 (in amperes) is

  1. 0 - j 40
  2. 0 + j 40
  3. 40 - j 40
  4. 40 + j 40
  5. 0


37. If Vs = 15 - j 20 V, R1 = 3 W, R2 = 4 W, X = 3 W, and b = 2 , the phasor voltage V2 (in volts) is

  1. -40 - j 30
  2. -40 + j 30
  3. 40 - j 30
  4. 40 + j 30
  5. 0


38. If R1 = 2 W, R2 = 4 W, X = 2 W, g = 0.125, and Is = 2 + j 0 A, the phasor voltage V2 (in volts) is

  1. 1 + j
  2. 1 - j
  3. -1 + j
  4. -1 - j
  5. 0


39. If Vs = 24+ j 0 V, R1 = 2 W, X = -4 W, and r = 2 W, the phasor current Ix (in amperes) is

  1. 0 + j 6
  2. 0 - j 6
  3. 3 - j 3
  4. 3 + j 3
  5. 0


40. If Vs = 24+ j 0 V, R1 = 2 W, X = -4 W, and r = 2 W, the phasor current Ix (in amperes) is

  1. 3 + j 3
  2. 3 - j 3
  3. 0 - j 6
  4. 0 + j 6
  5. 0


41. If g = 0.5 S, C = 0.125 F, and is (t) = cos(4 t) A, the forced response for the voltage vx(t) is

  1. 2 cos(4 t - 135o)
  2. 2 cos(4 t - 45o)
  3. 2 cos(4 t + 45o)
  4. 2 cos(4 t + 135o)
  5. 0


42. If g = 0.5 S, C = 0.125 F, and is (t) = cos(4 t) A, the forced response for the voltage vx(t) is

  1. 2 cos(4 t - 45o)
  2. 2 cos(4 t + 45o)
  3. 2 cos(4 t - 135o)
  4. 2 cos(4 t + 135o)
  5. 0


43. If Is = 2+ j 0 A, R = 3 W, and X = -4 W, the phasor voltage V0 (in volts) is

  1. -6 + j 8
  2. 6 + j 8
  3. 6 - j 8
  4. -6 - j 8
  5. 0


44. If is (t) = 2 cos(4 t) A, R = 3 W, and L = 1 H, the forced response for the voltage v0(t) is

  1. 10 cos(4 t + 53.1o)
  2. 10 cos(4 t - 53.1o)
  3. 10 cos(4 t + 36.9o)
  4. 10 cos(4 t + 36.9o)
  5. 0


45. If vs (t) = 2 cos(4 t) V, L = 2 H, and C = 1/32 F, the forced response for the voltage v0(t) is

  1. 2 cos(4 t)
  2. 2 cos(4 t - 90o)
  3. 2 cos(4 t + 90o)
  4. 2 cos(4 t - 45o)
  5. 2 cos(4 t + 45o)


46. If Vs = 3 + j 0 V, R = 12 W, and X = -12 W, the phasor voltage V0 (in volts) is

  1. 3 - j 3
  2. 3 + j 3
  3. 0 + j 3
  4. 0 - j 3
  5. 0


47. If vs (t) = 10cos(5 t) V, R1 = 10 W, R2 = 20 W, and C = 0.01 F, the forced response for the current i0(t) is

  1. 2 cos(5 t - 135o)
  2. 2 cos(5 t + 135o)
  3. 2 cos(5 t - 45o)
  4. 2 cos(5 t + 45o)
  5. 0


48. If Vs = 20 + j 0 V, R = 10 W, and X = 20 W, the phasor current I0 (in amperes) is

  1. 2 - j 2
  2. 2 + j 2
  3. -1 + j
  4. -1 - j
  5. 0


49. If Vs = 5+ j 0 V, R = 20 W, and X = -20 W, the phasor voltage V0 (in volts) is

  1. 0 - j 10
  2. 0 + j 10
  3. -5 + j 0
  4. 5 + j 0
  5. 0


50. If vs(t) = 2 cos(4 t) V, R = 20 W, and C = 0.025 F, the forced response for the voltage v0(t) is

  1. 8 cos(4 t + 180o)
  2. 8 cos(4 t)
  3. 8 cos(4 t + 90o)
  4. 8 cos(4 t - 90o)
  5. 0




End of Questions on AC Circuits

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