THE EE 101 CHALLENGE/FINAL EXAM QUESTION BANK BASIC CONCEPTS
SAN JOSE STATE UNIVERSITY
College of Engineering
ELECTRICAL ENGINEERING DEPARTMENT
SAN JOSE STATE UNIVERSITY
College of Engineering
ELECTRICAL ENGINEERING DEPARTMENT
THE EE 101 CHALLENGE/FINAL EXAM QUESTION BANK
EE 101 (Circuit Concepts and Problem Solving) is a one-unit, credit/no-credit course that is a prerequisite for EE 110 (Network Analysis) and EE 112 (Linear Systems). The prerequisites for EE 101 are a grade of C or better in EE 98 or equivalent.
To obtain credit for EE 101, students are required to
(1) enroll in the EE 101 semester course and
(2) achieve a passing score on the examination.
Note that students can either
(a) take the examination at the end of a semester of their enrollment, or
(b) "challenge" the course by taking the examination at the beginning of a semester.
Students are required to be registered in the EE 101 course in the semester that they take and pass the exam.
Well prepared students are encouraged to "challenge" the course. To help students prepare for this exam, this web site provides a collection of 305 questions and their answers. In every case, the first answer in the multiple-choice list of five choices is the correct answer. To avoid being biased by knowing the right answer ahead of time, we recommend that you work out your solution to each problem before looking at the answers.
The examination for EE 101 is closed book and closed notes. Only student ID and basic calculators are allowed. The questions on the actual exam will be created by selecting questions from the EE 101 Question Bank and modifying the questions slightly. Typical modifications include, but are not limited to, changing the numerical values of parameters and randomizing the answer sequence.
The following categories are:
The following 75 questions concern basic units, definitions, laws, and relations between important circuit quantities. In this version of the exam, the first choice is always the correct one. In the actual exam, the correct choice could be in any position, and there may be other changes to the choices. You can always assume that numerical values for the resistance of resistors, inductance of inductors and capacitance of capacitors are positive.
1. Charge is measured in
- coulombs
- volts
- amperes
- watts
- joules
2. Current is measured in
- amperes
- volts
- coulombs
- watts
- joules
3. Power is measured in
- watts
- volts
- coulombs
- amperes
- joules
4. Energy is measured in
- joules
- volts
- coulombs
- amperes
- watts
5. Resistance is measured in
- ohms
- henrys
- farads
- watts
- joules
6. Inductance is measured in
- henrys
- ohms
- farads
- watts
- joules
7. Capacitance is measured in
- farads
- henrys
- ohms
- watts
- joules
8. The current i through a capacitor and the charge q that it holds are related by
- i = dq/dt
- q = di/dt
- q = 0.5 i2
- i = 0.5 q2
- q i = 1
9. The magnetic flux linkage l in an inductor and the voltage v across its terminals are related by
- v = dl/dt
- l = dv/dt
- v = 0.5 l2
- l = 0.5 v2
- v l = 1
10. Kirchhoff's Voltage Law (KVL) can be stated as
- The sum of the voltage drops around any closed path is zero
- The sum of the voltages at all the nodes is zero
- The sum of the voltages across all the elements equals the sum of the currents through all the elements
- The voltage across an element is proportional to the current through the element
- The sum of the voltages into a node is equal to the sum of the voltages out of the node
11. Kirchhoff's Voltage Law (KVL) can be stated as
- The voltage rise from Node a to Node b is the same for every path from a to b
- The voltage rise from Node a to Node b is zero if Node b is a ground node
- The total voltage into a node equals the total voltage out of a node
- The voltage at Node a with Node b grounded is the same as the voltage at Node b with Node a grounded
- The voltage between any two nodes is independent of the total current flowing in the network
12. Kirchhoff's Current Law (KCL) can be stated as
- The sum of the currents flowing into any node is zero
- The sum of the currents flowing around any closed loop is zero
- The sum of the currents through all elements equals the sum of the voltages across the elements
- The current through an element is proportional to the voltage across the element
- The sum of the currents flowing clockwise around any mesh is equal to the sum of the currents flowing counterclockwise around the same mesh
13. Kirchhoff's Current Law (KCL) can be stated as
- The sum of the currents entering a node equals the sum of the currents leaving the node
- The sum of the currents entering a node equals the sum of the currents entering the ground node
- The current flowing around any mesh is independent of the voltage sources in that mesh
- The sum of the currents flowing around a mesh is zero
- The sum of the currents flowing through any element is equal to the voltage dropped across that element
14. When two or more circuit elements are connected in series
- the currents flowing through them are the same
- the voltages across them are the same
- the powers dissipated in them are the same
- the energies stored in them are the same
- the flux linkages produced by them are the same
15. When two or more circuit elements are connected in parallel
- the voltages across them are the same
- the currents flowing through them are the same
- the powers dissipated in them are the same
- the energies stored in them are the same
- the flux linkages produced by them are the same
16. The voltage v(t) across an independent voltage source
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17. The current i(t) through an independent current source
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18. The voltage vc for the dependent source shown
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19. The voltage vc for the dependent source shown
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20. The current ic for the dependent source shown
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21. The current ic for the dependent source shown
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22. The open-loop voltage gain of an ideal operational amplifier is
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23. The current flowing into either input of an ideal operational amplifier is
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24. The current i0 flowing out of an ideal operational amplifier is
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25. The circuit shown is called
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26. The circuit shown is called
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27. The circuit shown is called
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28. Ohm's Law is
- v = R i
- v = L di/dt
- p = i2 R
- p = v i
- i = C dv/dt
29. The resistance R and the conductance G of a resistor are related by
- G = 1 / R
- G = 2 p R
- G = 2 p / R
- R + G = 1
- G = e-R
30. The voltage v across an inductor and the current i through it are related by
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31. The voltage v across a capacitor and the current i through it are related by
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32. The relationship between power p and energy w is
- p = dw/dt
- w = dp/dt
- p = w2
- w = p2
- p = 1 / w
33. The instantaneous power p(t) flowing into a circuit element
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34. The energy w(t) transferred into a circuit element
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35. The power dissipated by a resistor is
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36. The power dissipated by a resistor is
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37. The power dissipated by a resistor
- cannot be negative
- is called the conductance
- is measured in joules
- is equal to the power that it generates
- is purely imaginary
38. The energy stored in an inductor L is given by
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39. The energy stored in a capacitor C is
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40. If a stable linear network is driven by a sinusoidal source, in steady state
- every voltage and every current has the same frequency
- every voltage and every current has the same amplitude
- every voltage and every current has the same phase
- all voltages and currents are constant
- the power absorbed by the resistive elements is equal to the power provided by the reactive elements
41. The angular frequency w (in rad/s) is related to the frequency f (in Hz) by
- w = 2 p f
- f = 2 p w
- w = 1 / f
- w = 2 p / f
- w + f = 1
42. If a voltage is given by v(t) = Vm cos(w t + f), the corresponding phasor voltage V is
- V = Vm ej f
- V = Vm ej w t
- V = Re{ Vm ej(w t + f) }
- V = 0.5(Vm + Vm *)
- V = j w Vm
43. If the phasor current for a frequency w is given by I = Im ej f , the corresponding time-domain current i(t) is
- i(t) = Im cos(w t + f)
- i(t) = Im ej(w t + f)
- i(t) = Im e- f t cos(w t)
- i(t) = Im e- w t cos(f t)
- i(t) = Im e- jw t cos(f t)
44. If a phasor voltage V is written in polar form as V = Vm ej f
- Vm is called the amplitude
- Vm is called the admittance
- f is called the frequency
- f is called the susceptance
- Vm is purely imaginary
45. If a phasor current I is written in polar form as I = Im ej f
- f is called the phase angle
- f is called the frequency
- Im is called the conductance
- Im is called the admittance
- Im is purely imaginary
46. The relationship between the phasor voltage V, the phasor current I and the impedance Z is
- V = Z I
- I = Z V
- Z = V I*
- Z = V + I
- Z = |V| |I| cos q
47. If I = Im ej f and Z = Zm ej q then the product Z I is given by
- Zm Im ej(q+f)
- Zm Im ej(q-f)
- Zm Im ej(qf)
- (Zm + Im) ej(q+f)
- (Zm + Im ) ej(qf)
48. The impedance Z and the admittance Y are related by
- Y = 1 / Z
- Y = 2 p Z
- Y = 2 p / Z
- Y + Z = 1
- Y = ej w Z
49. The impedance Z and the admittance Y are related by
- Y Z = 1
- Z = 2 p Y
- Z = 2 p / Y
- Z + Y = 1
- Z = ej w Y
50. If an impedance Z is written in rectangular form as Z = R +j X,
- X is called the reactance
- X cannot be positive
- X cannot be negative
- X must become infinite at high frequencies
- R and X are measured in different units
51. The impedance of an inductor L at angular frequency w is
- Z = j w L
- Z = 1 / j w L
- Z = 0.5 w 2
- Z = w L
- Z = 1 / w L
52. The impedance of an inductor is
- purely imaginary
- infinite at DC
- constant
- a sinusoidal function of frequency
- indeterminate
53. The reactance of an inductor L at angular frequency w is
- X = w L
- X = -w L
- X = 1 / w L
- X = - 1 / w L
- X = j w L
54. The reactance of an inductor
- is never negative
- is never positive
- decreases in magnitude as frequency increases
- decreases in magnitude as the inductance increases
- is equal to the energy stored in the inductor
55. The impedance of a capacitor C at angular frequency w is
- Z = 1 / j w C
- Z = j w C
- Z = 0.5 w2 C
- Z = w C
- Z = 1 / w C
56. The impedance of a capacitor is
- purely imaginary
- zero at DC
- constant
- a sinusoidal function of frequency
- indeterminate
57. The reactance of a capacitor C at angular frequency w is
- X = - 1 / w C
- X = 1 / w C
- X = -w C
- X = w C
- X = 1 / j w C
58. The reactance of a capacitor
- is never positive
- is never negative
- increases in magnitude as frequency increases
- increases as the capacitance increases
- is equal to the energy stored in the capacitor
59. The impedance of a resistor R at angular frequency w is
- Z = R
- Z = j R
- Z = j w R
- Z = 1 / R
- Z =1 / j w R
60. At very high frequencies, an inductor acts like
- an open circuit
- a short circuit
- a voltage source
- a capacitor
- an operational amplifier
61. At very low frequencies, an inductor acts like
- a short circuit
- an open circuit
- a current source
- a capacitor
- an operational amplifier
62. At very high frequencies, a capacitor acts like
- a short circuit
- an open circuit
- a current source
- an inductor
- an operational amplifier
63. At very low frequencies, a capacitor acts like
- an open circuit
- a short circuit
- a voltage source
- an inductor
- an operational amplifier
64. The equivalent impedance for three impedances connected in series is
65. The equivalent impedance for three impedances connected in parallel is
66. The circuit shown is called
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67. For the circuit shown
68. The circuit shown is called
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69. For the circuit shown,
70. An inactive or "dead" voltage source is equivalent to
- a short circuit
- an open circuit
- an ideal inductor
- an ideal capacitor
- an active or "live" current source
71. An inactive or "dead" current source is equivalent to
- an open circuit
- a short circuit
- an ideal inductor
- an ideal capacitor
- an active or "live" voltage source
72. The Thevenin equivalent impedance can be obtained by
- applying a test source with all independent sources dead
- applying a test source with all dependent sources dead
- short circuiting all inductors and open circuiting all capacitors
- open circuiting all inductors and short circuiting all capacitors
- replacing all inductors by capacitors and all capacitors by inductors
73. The Thevenin equivalent voltage can be obtained by
- solving for the open-circuit voltage
- solving for short-circuit voltage
- solving for the open-circuit current
- short circuiting all inductors and open circuiting all capacitors
- open circuiting all inductors and short circuiting all capacitors
74. The Norton equivalent current can be obtained by
- solving for the short-circuit current
- solving for the open-circuit current
- solving for the short-circuit voltage
- short circuiting all inductors and open circuiting all capacitors
- open circuiting all inductors and short circuiting all capacitors
75. The impedances in the Thevenin and Norton equivalent circuits
- are equal
- are complex conjugates of one another
- are negatives of one another
- are undefined when w is zero
- are undefined when w is infinite
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